Ranking of Florida Cities By Number of Robbery Crimes in 2015
According to the FBI UCR data, in 2015, the Florida city with the highest number of Robbery Crimes was Miami (1,681), followed by Jacksonville (1,398), Tampa (671), St. Petersburg (573), and Orlando (522).
The chart below shows the top 10 cities with high number of Robbery crimes in 2015, and the table below shows the ranking of Florida cities with high number of Robbery crimes.
You can see similar rankings of cities for other crime types in Florida, and the ranking of all cities in the US.
Hover over or click on the bars in the chart below, to see the number of Robbery crimes for each city. The data can also be found in a table below. You can use the table to sort, filter, and explore the data further.
You can also see this information for other states.
You can also find the rate of violent and property crimes for Florida cities.
Rank | City | Number of Crimes |
---|---|---|
1 | Miami | 1,681 |
2 | Jacksonville | 1,398 |
3 | Tampa | 671 |
4 | St. Petersburg | 573 |
5 | Orlando | 522 |
6 | Fort Lauderdale | 429 |
7 | Miami Beach | 418 |
8 | Tallahassee | 399 |
9 | Homestead | 312 |
10 | Pompano Beach | 311 |
11 | West Palm Beach | 277 |
12 | Hialeah | 265 |
13 | Gainesville | 231 |
14 | Hollywood | 226 |
15 | Miami Gardens | 219 |
16 | Lauderhill | 212 |
17 | Lake Worth | 197 |
18 | Clearwater | 181 |
19 | Fort Myers | 178 |
20 | North Miami | 169 |
21 | Boynton Beach | 153 |
22 | Daytona Beach | 147 |
23 | Melbourne | 134 |
24 | Lakeland | 131 |
25 | Delray Beach | 127 |