Ranking of Florida Cities By Number of Robbery Crimes in 2015

Updated on January 9, 2025.

According to the FBI UCR data, in 2015, the Florida city with the highest number of Robbery Crimes was Miami (1,681), followed by Jacksonville (1,398), Tampa (671), St. Petersburg (573), and Orlando (522).

The chart below shows the top 10 cities with high number of Robbery crimes in 2015, and the table below shows the ranking of Florida cities with high number of Robbery crimes.

You can see similar rankings of cities for other crime types in Florida, and the ranking of all cities in the US.

Hover over or click on the bars in the chart below, to see the number of Robbery crimes for each city. The data can also be found in a table below. You can use the table to sort, filter, and explore the data further.

You can also see this information for other states.

You can also find the rate of violent and property crimes for Florida cities.

Data Source: FBI UCR.
See this for other years:
Ranking of Florida Cities By Number of Robbery Crimes in 2015
Miami
1,681
Jacksonville
1,398
Tampa
671
St. Petersburg
573
Orlando
522
Fort Lauderdale
429
Miami Beach
418
Tallahassee
399
Homestead
312
Pompano Beach
311
Ranking of Florida Cities By Number of Robbery Crimes in 2015
Rank
City
Number of Crimes
1 Miami 1,681
2 Jacksonville 1,398
3 Tampa 671
4 St. Petersburg 573
5 Orlando 522
6 Fort Lauderdale 429
7 Miami Beach 418
8 Tallahassee 399
9 Homestead 312
10 Pompano Beach 311
11 West Palm Beach 277
12 Hialeah 265
13 Gainesville 231
14 Hollywood 226
15 Miami Gardens 219
16 Lauderhill 212
17 Lake Worth 197
18 Clearwater 181
19 Fort Myers 178
20 North Miami 169
21 Boynton Beach 153
22 Daytona Beach 147
23 Melbourne 134
24 Lakeland 131
25 Delray Beach 127
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