Ranking of United States Cities By Number of Larceny-Theft Crimes in 2015
Updated on January 9, 2025.
According to the FBI UCR data, in 2015, the US city with the highest number of Larceny-Theft Crimes was New York, NY (108,376); followed by Houston, TX (66,634); Los Angeles, CA (61,191); Chicago, IL (57,022); and San Antonio, TX (55,803).
The chart below shows the top 10 cities with high number of Larceny-Theft crimes in 2015, and the table below shows the ranking of the top 500 cities with high number of Larceny-Theft crimes in the United States.
You can see similar rankings of cities for other crime types in the United States.
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Related Topics: US FBI UCR 2015 Topic List.
Data Source: FBI UCR.
See this for other years:
Ranking of US Cities By Number of Larceny-Theft Crimes in 2015
Rank | City | Number of Crimes |
|---|---|---|
| 1 | New York, NY | 108,376 |
| 2 | Houston, TX | 66,634 |
| 3 | Los Angeles, CA | 61,191 |
| 4 | Chicago, IL | 57,022 |
| 5 | San Antonio, TX | 55,803 |
| 6 | San Francisco, CA | 40,918 |
| 7 | Philadelphia, PA | 36,228 |
| 8 | Phoenix, AZ | 34,288 |
| 9 | Tucson, AZ | 29,592 |
| 10 | Austin, TX | 28,068 |
| 11 | Seattle, WA | 26,199 |
| 12 | Dallas, TX | 26,076 |
| 13 | Indianapolis, IN | 25,301 |
| 14 | Washington, DC | 24,194 |
| 15 | Charlotte-Mecklenburg, NC | 24,091 |
| 16 | Memphis, TN | 24,049 |
| 17 | Las Vegas Metropolitan Police Department, NV | 24,010 |
| 18 | Jacksonville, FL | 23,456 |
| 19 | Columbus, OH | 23,021 |
| 20 | Albuquerque, NM | 22,818 |
| 21 | Fort Worth, TX | 21,489 |
| 22 | San Diego, CA | 18,933 |
| 23 | Louisville Metro, KY | 18,850 |
| 24 | Nashville Metropolitan, TN | 18,463 |
| 25 | Baltimore, MD | 17,658 |
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